5.06x^2-2.25x-1.49=0

Solution for 5.06x^2-2.25x-1.49=0 equation:

5.06x^2-2.25x-1.49=0

a = 5.06; b = -2.25; c = -1.49;
Δ = b2-4ac
Δ = -2.252-4·5.06·(-1.49)
Δ = 35.2201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.25)-\sqrt{35.2201}}{2*5.06}=\frac{2.25-\sqrt{35.2201}}{10.12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.25)+\sqrt{35.2201}}{2*5.06}=\frac{2.25+\sqrt{35.2201}}{10.12}
$